-6(n-5)+3n=-2(2n-4)+3n

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Solution for -6(n-5)+3n=-2(2n-4)+3n equation: 



-6(n-5)+3n=-2(2n-4)+3n

We move all terms to the left:

-6(n-5)+3n-(-2(2n-4)+3n)=0

We add all the numbers together, and all the variables

3n-6(n-5)-(-2(2n-4)+3n)=0

We multiply parentheses

3n-6n-(-2(2n-4)+3n)+30=0



We calculate terms in parentheses: -(-2(2n-4)+3n), so:

-2(2n-4)+3n

We add all the numbers together, and all the variables

3n-2(2n-4)

We multiply parentheses

3n-4n+8

We add all the numbers together, and all the variables

-1n+8

Back to the equation:

-(-1n+8)



We add all the numbers together, and all the variables

-3n-(-1n+8)+30=0

We get rid of parentheses

-3n+1n-8+30=0

We add all the numbers together, and all the variables

-2n+22=0

We move all terms containing n to the left, all other terms to the right

-2n=-22

n=-22/-2

n=+11

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