4x+2=(1/2x)+17

Solution for 4x+2=(1/2x)+17 equation:

4x+2=(1/2x)+17

We move all terms to the left:

4x+2-((1/2x)+17)=0


Domain of the equation: 2x)+17)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

4x-((+1/2x)+17)+2=0

We multiply all the terms by the denominator


4x*2x)+17)-((+2*2x)+17)+1=0

Wy multiply elements

8x^2+4x=0

a = 8; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·8·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*8}=\frac{-8}{16}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*8}=\frac{0}{16}
=0
$