4x+2(x+1)=7x-5(4-2x)

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Solution for 4x+2(x+1)=7x-5(4-2x) equation: 



4x+2(x+1)=7x-5(4-2x)

We move all terms to the left:

4x+2(x+1)-(7x-5(4-2x))=0

We add all the numbers together, and all the variables

4x+2(x+1)-(7x-5(-2x+4))=0

We multiply parentheses

4x+2x-(7x-5(-2x+4))+2=0



We calculate terms in parentheses: -(7x-5(-2x+4)), so:

7x-5(-2x+4)

We multiply parentheses

7x+10x-20

We add all the numbers together, and all the variables

17x-20

Back to the equation:

-(17x-20)



We add all the numbers together, and all the variables

6x-(17x-20)+2=0

We get rid of parentheses

6x-17x+20+2=0

We add all the numbers together, and all the variables

-11x+22=0

We move all terms containing x to the left, all other terms to the right

-11x=-22

x=-22/-11

x=+2

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