-11=5(u-3)3u

Solution for -11=5(u-3)3u equation:

-11=5(u-3)3u

We move all terms to the left:

-11-(5(u-3)3u)=0


We calculate terms in parentheses: -(5(u-3)3u), so:

5(u-3)3u

We multiply parentheses

15u^2-45u

Back to the equation:

-(15u^2-45u)


We get rid of parentheses

-15u^2+45u-11=0

a = -15; b = 45; c = -11;
Δ = b2-4ac
Δ = 452-4·(-15)·(-11)
Δ = 1365
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{1365}}{2*-15}=\frac{-45-\sqrt{1365}}{-30}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{1365}}{2*-15}=\frac{-45+\sqrt{1365}}{-30}
$