-2+3/4j+1/2j=2

Solution for -2+3/4j+1/2j=2 equation:

-2+3/4j+1/2j=2

We move all terms to the left:

-2+3/4j+1/2j-(2)=0


Domain of the equation: 4j!=0

j!=0/4

j!=0

j∈R



Domain of the equation: 2j!=0

j!=0/2

j!=0

j∈R


We add all the numbers together, and all the variables

3/4j+1/2j-4=0

We calculate fractions


6j/8j^2+4j/8j^2-4=0

We multiply all the terms by the denominator


6j+4j-4*8j^2=0

We add all the numbers together, and all the variables

10j-4*8j^2=0

Wy multiply elements

-32j^2+10j=0

a = -32; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-32)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-32}=\frac{-20}{-64}
=5/16
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-32}=\frac{0}{-64}
=0
$