4x+2(2x+5)=(x+3)-(8-x)

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Solution for 4x+2(2x+5)=(x+3)-(8-x) equation: 



4x+2(2x+5)=(x+3)-(8-x)

We move all terms to the left:

4x+2(2x+5)-((x+3)-(8-x))=0

We add all the numbers together, and all the variables

4x+2(2x+5)-((x+3)-(-1x+8))=0

We multiply parentheses

4x+4x-((x+3)-(-1x+8))+10=0



We calculate terms in parentheses: -((x+3)-(-1x+8)), so:

(x+3)-(-1x+8)

We get rid of parentheses

x+1x+3-8

We add all the numbers together, and all the variables

2x-5

Back to the equation:

-(2x-5)



We add all the numbers together, and all the variables

8x-(2x-5)+10=0

We get rid of parentheses

8x-2x+5+10=0

We add all the numbers together, and all the variables

6x+15=0

We move all terms containing x to the left, all other terms to the right

6x=-15

x=-15/6

x=-2+1/2

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