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(X+1)(X+2)=552
We move all terms to the left:
(X+1)(X+2)-(552)=0
We multiply parentheses ..
(+X^2+2X+X+2)-552=0
We get rid of parentheses
X^2+2X+X+2-552=0
We add all the numbers together, and all the variables
X^2+3X-550=0
a = 1; b = 3; c = -550;
Δ = b2-4ac
Δ = 32-4·1·(-550)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-47}{2*1}=\frac{-50}{2} =-25 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+47}{2*1}=\frac{44}{2} =22 $
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