9x-3(x-4)=6(x+2)

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Solution for 9x-3(x-4)=6(x+2) equation: 



9x-3(x-4)=6(x+2)

We move all terms to the left:

9x-3(x-4)-(6(x+2))=0

We multiply parentheses

9x-3x-(6(x+2))+12=0



We calculate terms in parentheses: -(6(x+2)), so:

6(x+2)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

6x-(6x+12)+12=0

We get rid of parentheses

6x-6x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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