9x+2(x-4)=13x-2(3-x)

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Solution for 9x+2(x-4)=13x-2(3-x) equation: 



9x+2(x-4)=13x-2(3-x)

We move all terms to the left:

9x+2(x-4)-(13x-2(3-x))=0

We add all the numbers together, and all the variables

9x+2(x-4)-(13x-2(-1x+3))=0

We multiply parentheses

9x+2x-(13x-2(-1x+3))-8=0



We calculate terms in parentheses: -(13x-2(-1x+3)), so:

13x-2(-1x+3)

We multiply parentheses

13x+2x-6

We add all the numbers together, and all the variables

15x-6

Back to the equation:

-(15x-6)



We add all the numbers together, and all the variables

11x-(15x-6)-8=0

We get rid of parentheses

11x-15x+6-8=0

We add all the numbers together, and all the variables

-4x-2=0

We move all terms containing x to the left, all other terms to the right

-4x=2

x=2/-4

x=-1/2

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