20=4(3x+3)+13x

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Solution for 20=4(3x+3)+13x equation: 



20=4(3x+3)+13x

We move all terms to the left:

20-(4(3x+3)+13x)=0



We calculate terms in parentheses: -(4(3x+3)+13x), so:

4(3x+3)+13x

We add all the numbers together, and all the variables

13x+4(3x+3)

We multiply parentheses

13x+12x+12

We add all the numbers together, and all the variables

25x+12

Back to the equation:

-(25x+12)



We get rid of parentheses

-25x-12+20=0

We add all the numbers together, and all the variables

-25x+8=0

We move all terms containing x to the left, all other terms to the right

-25x=-8

x=-8/-25

x=8/25

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