4x+13-(2x-(4(x-3)-5))=2(x-6

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Solution for 4x+13-(2x-(4(x-3)-5))=2(x-6 equation: 



4x+13-(2x-(4(x-3)-5))=2(x-6

We move all terms to the left:

4x+13-(2x-(4(x-3)-5))-(2(x-6)=0



We calculate terms in parentheses: -(2x-(4(x-3)-5)), so:

2x-(4(x-3)-5)



We calculate terms in parentheses: -(4(x-3)-5), so:

4(x-3)-5

We multiply parentheses

4x-12-5

We add all the numbers together, and all the variables

4x-17

Back to the equation:

-(4x-17)



We get rid of parentheses

2x-4x+17

We add all the numbers together, and all the variables

-2x+17

Back to the equation:

-(-2x+17)



We get rid of parentheses

4x+2x-(2(x-6)+13-17=0

We add all the numbers together, and all the variables

6x-(2(x-6)+13-17=0

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