4/3m-3=2-3/4m

Solution for 4/3m-3=2-3/4m equation:

4/3m-3=2-3/4m

We move all terms to the left:

4/3m-3-(2-3/4m)=0


Domain of the equation: 3m!=0

m!=0/3

m!=0

m∈R



Domain of the equation: 4m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

4/3m-(-3/4m+2)-3=0

We get rid of parentheses

4/3m+3/4m-2-3=0

We calculate fractions


16m/12m^2+9m/12m^2-2-3=0

We add all the numbers together, and all the variables

16m/12m^2+9m/12m^2-5=0

We multiply all the terms by the denominator


16m+9m-5*12m^2=0

We add all the numbers together, and all the variables

25m-5*12m^2=0

Wy multiply elements

-60m^2+25m=0

a = -60; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-60)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-60}=\frac{-50}{-120}
=5/12
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-60}=\frac{0}{-120}
=0
$