(4x+2)+(3x-7)=100

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Solution for (4x+2)+(3x-7)=100 equation: 



(4x+2)+(3x-7)=100

We move all terms to the left:

(4x+2)+(3x-7)-(100)=0

We get rid of parentheses

4x+3x+2-7-100=0

We add all the numbers together, and all the variables

7x-105=0

We move all terms containing x to the left, all other terms to the right

7x=105

x=105/7

x=15

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