-(2x-4+3)(x-1)=2(x-1)-(x-3)

Solution for -(2x-4+3)(x-1)=2(x-1)-(x-3) equation:

-(2x-4+3)(x-1)=2(x-1)-(x-3)

We move all terms to the left:

-(2x-4+3)(x-1)-(2(x-1)-(x-3))=0

We add all the numbers together, and all the variables

-(2x-1)(x-1)-(2(x-1)-(x-3))=0

We multiply parentheses ..

-(+2x^2-2x-1x+1)-(2(x-1)-(x-3))=0


We calculate terms in parentheses: -(2(x-1)-(x-3)), so:

2(x-1)-(x-3)

We multiply parentheses

2x-(x-3)-2

We get rid of parentheses

2x-x+3-2

We add all the numbers together, and all the variables

x+1

Back to the equation:

-(x+1)


We get rid of parentheses

-2x^2+2x+1x-x-1-1=0

We add all the numbers together, and all the variables

-2x^2+2x-2=0

a = -2; b = 2; c = -2;
Δ = b2-4ac
Δ = 22-4·(-2)·(-2)
Δ = -12
Delta is less than zero, so there is no solution for the equation