4x+12-x=1/3(9x-2-)

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Solution for 4x+12-x=1/3(9x-2-) equation: 



4x+12-x=1/3(9x-2-)

We move all terms to the left:

4x+12-x-(1/3(9x-2-))=0



Domain of the equation: 3(9x-2-))!=0

x∈R



We add all the numbers together, and all the variables

4x-x-(1/3(+9x))+12=0

We add all the numbers together, and all the variables

3x-(1/3(+9x))+12=0

We multiply all the terms by the denominator


3x*3(+9x))-(1+12*3(+9x))=0

Wy multiply elements

9x^2(++36x(+=0

We use the square of the difference formula

9x^2(+36x(+=0

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