5(z+1)=(2-3z)+17

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Solution for 5(z+1)=(2-3z)+17 equation: 



5(z+1)=(2-3z)+17

We move all terms to the left:

5(z+1)-((2-3z)+17)=0

We add all the numbers together, and all the variables

5(z+1)-((-3z+2)+17)=0

We multiply parentheses

5z-((-3z+2)+17)+5=0



We calculate terms in parentheses: -((-3z+2)+17), so:

(-3z+2)+17

We get rid of parentheses

-3z+2+17

We add all the numbers together, and all the variables

-3z+19

Back to the equation:

-(-3z+19)



We get rid of parentheses

5z+3z-19+5=0

We add all the numbers together, and all the variables

8z-14=0

We move all terms containing z to the left, all other terms to the right

8z=14

z=14/8

z=1+3/4

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