5(2x+3)=1/2(20x+6

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Solution for 5(2x+3)=1/2(20x+6 equation: 



5(2x+3)=1/2(20x+6

We move all terms to the left:

5(2x+3)-(1/2(20x+6)=0



Domain of the equation: 2(20x+6)!=0

x∈R



We multiply parentheses

10x-(1/2(20x+6)+15=0

We multiply all the terms by the denominator


10x*2(20x+6)+15-(1=0

We add all the numbers together, and all the variables

10x*2(20x+6)=0

Wy multiply elements

20x^2(2=0

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