4x+(3x+1)=6-2(x+1)

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Solution for 4x+(3x+1)=6-2(x+1) equation: 



4x+(3x+1)=6-2(x+1)

We move all terms to the left:

4x+(3x+1)-(6-2(x+1))=0

We get rid of parentheses

4x+3x-(6-2(x+1))+1=0



We calculate terms in parentheses: -(6-2(x+1)), so:

6-2(x+1)

determiningTheFunctionDomain
-2(x+1)+6

We multiply parentheses

-2x-2+6

We add all the numbers together, and all the variables

-2x+4

Back to the equation:

-(-2x+4)



We add all the numbers together, and all the variables

7x-(-2x+4)+1=0

We get rid of parentheses

7x+2x-4+1=0

We add all the numbers together, and all the variables

9x-3=0

We move all terms containing x to the left, all other terms to the right

9x=3

x=3/9

x=1/3

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