4x+(1.5x2)=17

Solution for 4x+(1.5x2)=17 equation:

4x+(1.5x^2)=17

We move all terms to the left:

4x+(1.5x^2)-(17)=0

We get rid of parentheses

1.5x^2+4x-17=0

a = 1.5; b = 4; c = -17;
Δ = b2-4ac
Δ = 42-4·1.5·(-17)
Δ = 118
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-\sqrt{118}}{2*1.5}=\frac{-4-\sqrt{118}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+\sqrt{118}}{2*1.5}=\frac{-4+\sqrt{118}}{3}
$