(4x-2)(2x-5)=

Solution for (4x-2)(2x-5)= equation:

(4x-2)(2x-5)=

We move all terms to the left:

(4x-2)(2x-5)-()=0

We add all the numbers together, and all the variables

(4x-2)(2x-5)=0

We multiply parentheses ..

(+8x^2-20x-4x+10)=0

We get rid of parentheses

8x^2-20x-4x+10=0

We add all the numbers together, and all the variables

8x^2-24x+10=0

a = 8; b = -24; c = +10;
Δ = b2-4ac
Δ = -242-4·8·10
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-16}{2*8}=\frac{8}{16}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+16}{2*8}=\frac{40}{16}
=2+1/2
$