(-3x-2)(x-3)=

Solution for (-3x-2)(x-3)= equation:

(-3x-2)(x-3)=

We move all terms to the left:

(-3x-2)(x-3)-()=0

We add all the numbers together, and all the variables

(-3x-2)(x-3)=0

We multiply parentheses ..

(-3x^2+9x-2x+6)=0

We get rid of parentheses

-3x^2+9x-2x+6=0

We add all the numbers together, and all the variables

-3x^2+7x+6=0

a = -3; b = 7; c = +6;
Δ = b2-4ac
Δ = 72-4·(-3)·6
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-11}{2*-3}=\frac{-18}{-6}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+11}{2*-3}=\frac{4}{-6}
=-2/3
$