4x(x-8)+45=5(5x-7/10)+4x

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Solution for 4x(x-8)+45=5(5x-7/10)+4x equation: 



4x(x-8)+45=5(5x-7/10)+4x

We move all terms to the left:

4x(x-8)+45-(5(5x-7/10)+4x)=0



Domain of the equation: 10)+4x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

4x(x-8)-(5(+5x-7/10)+4x)+45=0

We multiply parentheses

4x^2-32x-(5(+5x-7/10)+4x)+45=0

We multiply all the terms by the denominator


4x^2*10)+4x)-32x*10)+4x)-(5(+5x-7+45*10)+4x)=0

We add all the numbers together, and all the variables

4x^2*10)+4x)-32x*10)+4x)-(5(5x+443)+4x)=0

Wy multiply elements

400x^4=0

We do not support expression: x^4

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