(2x+20)+(-x+100)+(3x-60)+(x+80)=360

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Solution for (2x+20)+(-x+100)+(3x-60)+(x+80)=360 equation: 



(2x+20)+(-x+100)+(3x-60)+(x+80)=360

We move all terms to the left:

(2x+20)+(-x+100)+(3x-60)+(x+80)-(360)=0

We add all the numbers together, and all the variables

(2x+20)+(-1x+100)+(3x-60)+(x+80)-360=0

We get rid of parentheses

2x-1x+3x+x+20+100-60+80-360=0

We add all the numbers together, and all the variables

5x-220=0

We move all terms containing x to the left, all other terms to the right

5x=220

x=220/5

x=44

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