7y/(3-6y)=12/5

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Solution for 7y/(3-6y)=12/5 equation: 



7y/(3-6y)=12/5

We move all terms to the left:

7y/(3-6y)-(12/5)=0



Domain of the equation: (3-6y)!=0

We move all terms containing y to the left, all other terms to the right

-6y!=-3

y!=-3/-6

y!=1/2

y∈R



We add all the numbers together, and all the variables

7y/(-6y+3)-(+12/5)=0

We get rid of parentheses

7y/(-6y+3)-12/5=0

We calculate fractions


35y/(-30y+15)+(72y-36)/(-30y+15)=0

We multiply all the terms by the denominator


35y+(72y-36)=0

We get rid of parentheses

35y+72y-36=0

We add all the numbers together, and all the variables

107y-36=0

We move all terms containing y to the left, all other terms to the right

107y=36

y=36/107

y=36/107

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