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4x(x+13)=0
We multiply parentheses
4x^2+52x=0
a = 4; b = 52; c = 0;
Δ = b2-4ac
Δ = 522-4·4·0
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-52}{2*4}=\frac{-104}{8} =-13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+52}{2*4}=\frac{0}{8} =0 $
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