16+3(1-2x)=4(x+3)

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Solution for 16+3(1-2x)=4(x+3) equation: 



16+3(1-2x)=4(x+3)

We move all terms to the left:

16+3(1-2x)-(4(x+3))=0

We add all the numbers together, and all the variables

3(-2x+1)-(4(x+3))+16=0

We multiply parentheses

-6x-(4(x+3))+3+16=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

-6x-(4x+12)+19=0

We get rid of parentheses

-6x-4x-12+19=0

We add all the numbers together, and all the variables

-10x+7=0

We move all terms containing x to the left, all other terms to the right

-10x=-7

x=-7/-10

x=7/10

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