6(2/3x-3)=3(1/3x+1

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Solution for 6(2/3x-3)=3(1/3x+1 equation: 



6(2/3x-3)=3(1/3x+1

We move all terms to the left:

6(2/3x-3)-(3(1/3x+1)=0



Domain of the equation: 3x-3)!=0

x∈R





Domain of the equation: 3x+1)!=0

x∈R



We multiply parentheses

12x-(3(1/3x+1)-18=0

We multiply all the terms by the denominator


12x*3x+1)-18-(3(1=0

We add all the numbers together, and all the variables

12x*3x=0

Wy multiply elements

36x^2=0

a = 36; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·36·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{72}=0$

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