4x(x+1)=143

Solution for 4x(x+1)=143 equation:

4x(x+1)=143

We move all terms to the left:

4x(x+1)-(143)=0

We multiply parentheses

4x^2+4x-143=0

a = 4; b = 4; c = -143;
Δ = b2-4ac
Δ = 42-4·4·(-143)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-48}{2*4}=\frac{-52}{8}
=-6+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+48}{2*4}=\frac{44}{8}
=5+1/2
$