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15+(5-x(/x))=30
We move all terms to the left:
15+(5-x(/x))-(30)=0
Domain of the equation: x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(5-x(+/x))+15-30=0
We add all the numbers together, and all the variables
(5-x(+/x))-15=0
We multiply all the terms by the denominator
(5-x(+-15*x))=0
We calculate terms in parentheses: +(5-x(+-15*x)), so:We get rid of parentheses
5-x(+-15*x)
determiningTheFunctionDomain -x(+-15*x)+5
We add all the numbers together, and all the variables
-x(-15x)+5
We multiply parentheses
15x^2+5
Back to the equation:
+(15x^2+5)
15x^2+5=0
a = 15; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·15·5
Δ = -300
Delta is less than zero, so there is no solution for the equation
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