42=-3(22-x)+3(x-2)

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Solution for 42=-3(22-x)+3(x-2) equation: 



42=-3(22-x)+3(x-2)

We move all terms to the left:

42-(-3(22-x)+3(x-2))=0

We add all the numbers together, and all the variables

-(-3(-1x+22)+3(x-2))+42=0



We calculate terms in parentheses: -(-3(-1x+22)+3(x-2)), so:

-3(-1x+22)+3(x-2)

We multiply parentheses

3x+3x-66-6

We add all the numbers together, and all the variables

6x-72

Back to the equation:

-(6x-72)



We get rid of parentheses

-6x+72+42=0

We add all the numbers together, and all the variables

-6x+114=0

We move all terms containing x to the left, all other terms to the right

-6x=-114

x=-114/-6

x=+19

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