4r2+9=12r

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Solution for 4r2+9=12r equation: 



4r^2+9=12r

We move all terms to the left:

4r^2+9-(12r)=0

a = 4; b = -12; c = +9;
Δ = b2-4ac
Δ = -122-4·4·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{12}{8}=1+1/2$

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