If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x+20x^2=0
a = 20; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·20·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*20}=\frac{-8}{40} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*20}=\frac{0}{40} =0 $
| -8(2-5a)=2+40a | | 9^x+1=24+9^x | | 2.9x-18.44=3.6 | | 3.9x-9.79=2.3 | | 300=2x+5x | | 12x+45=3x-11 | | -4*3p=60 | | T5=3^n-1 | | 4.678-0.8n=6.2+0.2(3.1n+6.59) | | y=900+39,750 | | -8-4(12n-9)=-6(1+8n) | | 3t^2+37t-14=0 | | 3x^2+37x-14=0 | | 9s+4=144 | | 4x+1/x+1-3=12/x^2-1 | | w/14=2 | | 3x-21=2x-1 | | 2a-3/a-1=2a+3/a+1+10/a^2-1 | | 3/4+x-2/x+14=0 | | 4x+10-4x=10 | | x=^2+7x-13=0 | | x=^2+6x-10=0 | | 7(4x+1)=4x-9x= | | y=-6,y=9 | | 8-4x=3(1−3x) | | 8−4x=3(1−3x) | | 1/2x+40=x | | 40+1/2x=x | | 6x/7=8+10/7 | | 40+.5x=x | | (180-x)=1/2(x)+9 | | 20+.5x=x |