4m=2(m+1)+3(m-1)

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Solution for 4m=2(m+1)+3(m-1) equation: 



4m=2(m+1)+3(m-1)

We move all terms to the left:

4m-(2(m+1)+3(m-1))=0



We calculate terms in parentheses: -(2(m+1)+3(m-1)), so:

2(m+1)+3(m-1)

We multiply parentheses

2m+3m+2-3

We add all the numbers together, and all the variables

5m-1

Back to the equation:

-(5m-1)



We get rid of parentheses

4m-5m+1=0

We add all the numbers together, and all the variables

-1m+1=0

We move all terms containing m to the left, all other terms to the right

-m=-1

m=-1/-1

m=1

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