25=3c-3(6-2c)

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Solution for 25=3c-3(6-2c) equation: 



25=3c-3(6-2c)

We move all terms to the left:

25-(3c-3(6-2c))=0

We add all the numbers together, and all the variables

-(3c-3(-2c+6))+25=0



We calculate terms in parentheses: -(3c-3(-2c+6)), so:

3c-3(-2c+6)

We multiply parentheses

3c+6c-18

We add all the numbers together, and all the variables

9c-18

Back to the equation:

-(9c-18)



We get rid of parentheses

-9c+18+25=0

We add all the numbers together, and all the variables

-9c+43=0

We move all terms containing c to the left, all other terms to the right

-9c=-43

c=-43/-9

c=4+7/9

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