3(2n+4)=6(6n+2)+7

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Solution for 3(2n+4)=6(6n+2)+7 equation: 



3(2n+4)=6(6n+2)+7

We move all terms to the left:

3(2n+4)-(6(6n+2)+7)=0

We multiply parentheses

6n-(6(6n+2)+7)+12=0



We calculate terms in parentheses: -(6(6n+2)+7), so:

6(6n+2)+7

We multiply parentheses

36n+12+7

We add all the numbers together, and all the variables

36n+19

Back to the equation:

-(36n+19)



We get rid of parentheses

6n-36n-19+12=0

We add all the numbers together, and all the variables

-30n-7=0

We move all terms containing n to the left, all other terms to the right

-30n=7

n=7/-30

n=-7/30

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