3(b+1)+5=20

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Solution for 3(b+1)+5=20 equation: 



3(b+1)+5=20

We move all terms to the left:

3(b+1)+5-(20)=0

We add all the numbers together, and all the variables

3(b+1)-15=0

We multiply parentheses

3b+3-15=0

We add all the numbers together, and all the variables

3b-12=0

We move all terms containing b to the left, all other terms to the right

3b=12

b=12/3

b=4

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