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4=(2/5)u
We move all terms to the left:
4-((2/5)u)=0
Domain of the equation: 5)u)!=0We add all the numbers together, and all the variables
u!=0/1
u!=0
u∈R
-((+2/5)u)+4=0
We multiply all the terms by the denominator
-((+2+4*5)u)=0
We calculate terms in parentheses: -((+2+4*5)u), so:u=0/-22
(+2+4*5)u
We add all the numbers together, and all the variables
22u
Back to the equation:
-(22u)
u=0
Równanie nie ma rozwiązania
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