.03x+.06(22000-x)=1050

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Solution for .03x+.06(22000-x)=1050 equation: 



.03x+.06(22000-x)=1050

We move all terms to the left:

.03x+.06(22000-x)-(1050)=0

We add all the numbers together, and all the variables

.03x+.06(-1x+22000)-1050=0

We multiply parentheses

.03x-0.06x+1320-1050=0

We add all the numbers together, and all the variables

-0.03x+270=0

We move all terms containing x to the left, all other terms to the right

-0.03x=-270

x=-270/-0.03

x=+9000

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