4x-3/2(5x-4)=5x+1/8(x+6)

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Solution for 4x-3/2(5x-4)=5x+1/8(x+6) equation: 



4x-3/2(5x-4)=5x+1/8(x+6)

We move all terms to the left:

4x-3/2(5x-4)-(5x+1/8(x+6))=0



Domain of the equation: 2(5x-4)!=0

x∈R





Domain of the equation: 8(x+6))!=0

x∈R



We calculate fractions


4x+(-24xx/(2(5x-4)*8(x+6)))+(-(5x+2x5)/(2(5x-4)*8(x+6)))=0



We calculate terms in parentheses: +(-24xx/(2(5x-4)*8(x+6))), so:

-24xx/(2(5x-4)*8(x+6))

We multiply all the terms by the denominator


-24xx

Back to the equation:

+(-24xx)





We calculate terms in parentheses: +(-(5x+2x5)/(2(5x-4)*8(x+6))), so:

-(5x+2x5)/(2(5x-4)*8(x+6))

We add all the numbers together, and all the variables

-(+5x+2x^5)/(2(5x-4)*8(x+6))

We multiply all the terms by the denominator


-(+5x+2x^5)

We do not support expression: x^5

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