7(3y+1)=-26

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Solution for 7(3y+1)=-26 equation: 



7(3y+1)=-26

We move all terms to the left:

7(3y+1)-(-26)=0

We add all the numbers together, and all the variables

7(3y+1)+26=0

We multiply parentheses

21y+7+26=0

We add all the numbers together, and all the variables

21y+33=0

We move all terms containing y to the left, all other terms to the right

21y=-33

y=-33/21

y=-1+4/7

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