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4=(-16t)(-16t)+120+4
We move all terms to the left:
4-((-16t)(-16t)+120+4)=0
We multiply parentheses ..
-((+256t^2)+120+4)+4=0
We calculate terms in parentheses: -((+256t^2)+120+4), so:We get rid of parentheses
(+256t^2)+120+4
We add all the numbers together, and all the variables
(+256t^2)+124
We get rid of parentheses
256t^2+124
Back to the equation:
-(256t^2+124)
-256t^2-124+4=0
We add all the numbers together, and all the variables
-256t^2-120=0
a = -256; b = 0; c = -120;
Δ = b2-4ac
Δ = 02-4·(-256)·(-120)
Δ = -122880
Delta is less than zero, so there is no solution for the equation
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