3(3-b)-29=21b-4(5+6b)

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Solution for 3(3-b)-29=21b-4(5+6b) equation: 



3(3-b)-29=21b-4(5+6b)

We move all terms to the left:

3(3-b)-29-(21b-4(5+6b))=0

We add all the numbers together, and all the variables

3(-1b+3)-(21b-4(6b+5))-29=0

We multiply parentheses

-3b-(21b-4(6b+5))+9-29=0



We calculate terms in parentheses: -(21b-4(6b+5)), so:

21b-4(6b+5)

We multiply parentheses

21b-24b-20

We add all the numbers together, and all the variables

-3b-20

Back to the equation:

-(-3b-20)



We add all the numbers together, and all the variables

-3b-(-3b-20)-20=0

We get rid of parentheses

-3b+3b+20-20=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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