8x2+2x=40

Solution for 8x2+2x=40 equation:

8x^2+2x=40

We move all terms to the left:

8x^2+2x-(40)=0

a = 8; b = 2; c = -40;
Δ = b2-4ac
Δ = 22-4·8·(-40)
Δ = 1284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1284}=\sqrt{4*321}=\sqrt{4}*\sqrt{321}=2\sqrt{321}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{321}}{2*8}=\frac{-2-2\sqrt{321}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{321}}{2*8}=\frac{-2+2\sqrt{321}}{16}
$