49=3(2c-5)+5

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Solution for 49=3(2c-5)+5 equation: 



49=3(2c-5)+5

We move all terms to the left:

49-(3(2c-5)+5)=0



We calculate terms in parentheses: -(3(2c-5)+5), so:

3(2c-5)+5

We multiply parentheses

6c-15+5

We add all the numbers together, and all the variables

6c-10

Back to the equation:

-(6c-10)



We get rid of parentheses

-6c+10+49=0

We add all the numbers together, and all the variables

-6c+59=0

We move all terms containing c to the left, all other terms to the right

-6c=-59

c=-59/-6

c=9+5/6

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