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8x^2-12x=12x
We move all terms to the left:
8x^2-12x-(12x)=0
We add all the numbers together, and all the variables
8x^2-24x=0
a = 8; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·8·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*8}=\frac{0}{16} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*8}=\frac{48}{16} =3 $
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