(x+3)2+(x-3)2=(x+5)2

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Solution for (x+3)2+(x-3)2=(x+5)2 equation: 



(x+3)2+(x-3)2=(x+5)2

We move all terms to the left:

(x+3)2+(x-3)2-((x+5)2)=0

We multiply parentheses

2x+2x-((x+5)2)+6-6=0



We calculate terms in parentheses: -((x+5)2), so:

(x+5)2

We multiply parentheses

2x+10

Back to the equation:

-(2x+10)



We add all the numbers together, and all the variables

4x-(2x+10)=0

We get rid of parentheses

4x-2x-10=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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