441=x(2x-1)

Solution for 441=x(2x-1) equation:

441=x(2x-1)

We move all terms to the left:

441-(x(2x-1))=0


We calculate terms in parentheses: -(x(2x-1)), so:

x(2x-1)

We multiply parentheses

2x^2-1x

Back to the equation:

-(2x^2-1x)


We get rid of parentheses

-2x^2+1x+441=0

We add all the numbers together, and all the variables

-2x^2+x+441=0

a = -2; b = 1; c = +441;
Δ = b2-4ac
Δ = 12-4·(-2)·441
Δ = 3529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{3529}}{2*-2}=\frac{-1-\sqrt{3529}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{3529}}{2*-2}=\frac{-1+\sqrt{3529}}{-4}
$