(3/4)*(4*x-3)=9

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Solution for (3/4)*(4*x-3)=9 equation:



(3/4)(4x-3)=9
We move all terms to the left:
(3/4)(4x-3)-(9)=0
Domain of the equation: 4)(4x-3)!=0
x∈R
We add all the numbers together, and all the variables
(+3/4)(4x-3)-9=0
We multiply parentheses ..
(+12x^2+3/4*-3)-9=0
We multiply all the terms by the denominator
(+12x^2+3-9*4*-3)=0
We get rid of parentheses
12x^2+3-3-9*4*=0
We add all the numbers together, and all the variables
12x^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$

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