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6k^2-42k+72=0
a = 6; b = -42; c = +72;
Δ = b2-4ac
Δ = -422-4·6·72
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-6}{2*6}=\frac{36}{12} =3 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+6}{2*6}=\frac{48}{12} =4 $
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