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(4y-2)(6-y)=0
We add all the numbers together, and all the variables
(4y-2)(-1y+6)=0
We multiply parentheses ..
(-4y^2+24y+2y-12)=0
We get rid of parentheses
-4y^2+24y+2y-12=0
We add all the numbers together, and all the variables
-4y^2+26y-12=0
a = -4; b = 26; c = -12;
Δ = b2-4ac
Δ = 262-4·(-4)·(-12)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-22}{2*-4}=\frac{-48}{-8} =+6 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+22}{2*-4}=\frac{-4}{-8} =1/2 $
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